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[LeetCode] Valid Anagram (easy / javascript)개발/알고리즘 2022. 6. 25. 18:01
const isAnagram = function(s, t) {
if(s.length !== t.length) return false;
s = [...s].sort();
t = [...t].sort();
for(let i=0; i<s.length; i++) {
if(s[i] === t[i]) continue;
if(s[i] === t[i+1] && s[i+1] === t[i]) {
i++
continue;
} else {
return false;
}
}
return true;
};효율성 똥 ..
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